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5r^2-37r+14=0
a = 5; b = -37; c = +14;
Δ = b2-4ac
Δ = -372-4·5·14
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-33}{2*5}=\frac{4}{10} =2/5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+33}{2*5}=\frac{70}{10} =7 $
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